How do you solve this formula

2^{x+1}=16

Solution:

\left\{3\right\}

Calculated: \left\{3.0\right\}

Derivative

\frac{d}{d x} 2^{x + 1} = 16

Complex Roots

\left\{x \mid x \in \C \wedge 2^{x + 1} - 16 = 0 \right\}