Math and Quadratic Equations

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Find the value of x
G(x)=20
Subject
Level
Highschool
Grade
11
How to solve this

\text{g)}\frac{x^{2}-1}{2x-3}\times\frac{6x-9}{3x+3}

Subject
Level
Learning For Fun
Subject
Level
Junior High
Grade
8

5x*2-7x-6=0 by quadratic formula method


 

Subject
Level
Highschool
Grade
10
Solve the following quadratic equation for x
7x^2-6x-13=0
Subject
Level
Highschool
Grade
10

 Firld the zeroes of the giver pdy7iortials 2x3 -6M i PCa) = a-2x+1 

Subject
Level
Highschool
Grade
10
9x8=_x 12=
Subject
Level
Middle School
Grade
4

 After going through this lesson, you are expected to illustrates quadratic equations and solves quadratic equations by: (a) extracting square roots; (c) completing the square; and (b) factoring; (d) using the quadratic formula. You learned about linear equation in one variable which id in the form of ax + b- 0, where a is not 0 otherwise the equation is constant. Quadratic equation is in the form of ax? + bx + c = 0 and a cannot be zero otherwise the equation will become linear equation. Learning Task 1. Group the given equations into two based on observed common properties. na - 3n + 10 -0 8-3k- 12 2y --9 2x + 2x + 1 -0 25b- 16 -0 3r + 2e- -6 5w +5-0 a- 31 + 2 = o d- 3e-7 + 2m-4 10u - 5- 8 a- 225 

Subject
Level
Highschool
Grade
9
Subject
Level
Highschool
Grade
9
Subject
Level
Highschool
Grade
4
Subject
Level
Highschool
Grade
10
How do you solve x times three
Subject
Level
Primary
Grade
6
What is the square root of 144?
Subject
Level
Highschool
Grade
10
What is 12x1=
Subject
Level
Middle School
Grade
5
Given that f(x) =2x exponent 3+px exponent 2 + qx + 18 is divided by x+1 find the remainder
Subject
Level
Highschool
Grade
10
X+7=10
Subject
Level
Highschool
Grade
8
What is 7x7
Subject
Level
Primary
Grade
4
k^2+5k+6
Subject
Level
Highschool
Grade
2
How do you solve this ben bought 4 packs of gum to share With his friends. Each pack has 10 pieces. 8 People are sharing the gum. How many pieces will each person get?
Subject
Level
University
Year
3
How to solve 2[7*2+8]2
Subject
Level
Highschool
Grade
3
What is x ×13
Subject
Level
Middle School
Grade
6
Subject
Level
Highschool
Grade
8
What are parentheses
Subject
Level
Primary
Grade
3
x^2-(√2+1)x+√2=0
Subject
Level
Primary
Grade
10
(3a-9) =
Subject
Level
Middle School
Grade
6
Express the above question
Subject
Level
Highschool
Grade
9
(5x-2y)²
Subject
Level
Junior High
Grade
9
Find the roots of the following x+
Subject
Level
Highschool
Grade
10
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